Question 139207

Graph the line with slope 1/3  passing through the point (3,1) . 

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Form: y = (1/3)x + b
you have y=1 when x = 3; solve for "b".
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1 = (1/3)3 + b
b = 0
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EQUATION:
y = (1/3)x
{{{graph(400,300,-10,10,-10,10,(1/3)x)}}}
Cheers,
Stan H.