Question 139188
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 


where {{{a=25}}}, {{{b=-20}}}, and {{{c=3}}}


{{{x = (-(-20) +- sqrt( (-20)^2-4*(25)*(3) ))/(2*(25)) }}} 


{{{x = (20 +- sqrt(400-300))/50 }}} 


{{{x = (20 +- sqrt(100))/50 }}}


{{{x = (20 +- 10)/50 }}} 


{{{x = 30/50=3/5}}} or {{{x=10/50=1/5}}} 


Apparently your arithmetic was faulty.  Go back and compare your work to mine.  


<big><b>Super-Double-Plus-Extra Credit: </big></b> How could you tell for certain that {{{1/5}}} and {{{3/5}}} are the actual roots of the equation?  (There are 2 different methods)