<PRE><B>Question 21115</B>
Let the lesser integer be x, then the next consecutive odd integer is (x+2).

Twice the greater (2(x+2)) is (=) 13 less than three times the lesser (3(x)-13)

Putting it all into an equation:

{{{2(x+2) = 3x - 13}}} Simplify and solve for x.
{{{2x + 4 = 3x - 13}}} Subtract 2x from both sides.
{{{4 = x - 13}}} Add 13 to both sides.
{{{x = 17}}}

The two consecutive odd integers are:  17 and 19

Check:

Twice 19 = 38
13 less than three times 17 = 51 - 13 = 38</PRE>