Question 139122
What is f(x + 1) if f(x)= 6x^3 - 3x^2 + 4x - 9

f(x+1) = 6(x+1)^3 - 3(x+1)^2 + 4(x+1) - 9

f(x+1) = 6[x^3+3x^2+3x+1] -3[x^2+2x+1] + 4x+4 -9

f(x+1) = 6x^3 +15x^2 +16x -2

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Cheers,
Stan H.