Question 139129
How many and what type of solutions will the equation have? 4a^2 + 4a + 2 = 0
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Using the quadratic formula you get:

a = [-4 +- sqrt(16 -4*4*2)]/8

a = [-4 +- sqrt(-16)]/8

a = [-4 +- 4i]/8

a = (-1+i)/2 or a = (-1-i)/2


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Cheers,
Stan H.