Question 139101
Let a=96, c=2.5b+4
a^2+b^2=c^2
96^2+b^2=(2.5b+4)^2
9216+b^2=6.25b^2+20b+16
5.25b^2+20b-9200=0
b=40" (see below)
c=2.5*40+4=104"
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Check:
9216+1600=10816
104^2=10816
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Ed
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*[invoke solve_quadratic_equation 5.25, 20, -9200]