Question 139127
{{{10x^2 - 16x + 6 = 0}}}
Use the quadratic formula  
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
when equation is in the form
{{{ax^2 + bx + c = 0}}}
{{{a = 10}}}
{{{b = -16}}}
{{{c = 6}}}
{{{x = (-(-16) +- sqrt( (-16)^2-4*10*6 ))/(2*10) }}}
{{{x = (16 +- sqrt( 256 - 240 ))/20 }}}
{{{x = (16 +- sqrt( 16 ))/20 }}}
{{{x = (16 + 4) / 20}}}
{{{x = 1}}} answer
{{{x = (16 - 4)/ 20}}}
{{{x = 3/5}}} answer