<PRE><B>Question 139080</B>
One brine solution contains 6% salt and another brine solution contains 2% salt. How many pints of each solution should be mixed to produce 48 pints of brine solution that is 5% salt?
:
Let x = amt of 6% salt solution
It says the final amt will be 48 pints, therefore
(48-x) = amt of 2% solution
:
.06x + .02(48-x) = .05(48)
.06x + .96 - .02x = 2.4
.06x - .02x = 2.4 - .96
.04x = 1.44
x = {{{1.44/.04}}}
x = 36 pints of 6% solution
and
48 - 36 = 12 pints of 2% solution
:
:
Check our answers in the original equation
.06(36) + .02(12) = .05(48)
 2.16 + .24 = 2.4</PRE>