Question 138979
Each of the terms in your numerator has a common factor of 10, so take that out of each of the terms leaving you with {{{10(x^2-3x+2)}}} for your numerator.  Now factor the trinomial in the numerator.  Since you did end up with {{{x+1}}} in your denominator, you apparently factored the denominator correctly as the difference of two squares.  So if you do the numerator correctly, you should have it.