Question 138891
LET X BE THE VALUE OF THE FIRST BATTERY.
THEN:
X+X/2+3X=54
(2X+X+6X)/2=54
9X=108
X=108/9
X=12 VOLTS FOR THE FIRST BATTERY.
12/2=6 VOLTS FOR THE SECOND BATTERY.
3*12=36 VOLTE FOT THE THIRD BATTERY.
PROOF:
12+6+36=54
54=54