Question 138830
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

Given: {{{-x+4x+32=0}}}
In this equation, a = -1, b = 4 and c = 32

{{{x = (-4 +- sqrt( 4^2-4*(-1)*32 ))/(2*(-1)) }}} 

{{{x = (-4 +- sqrt( 16+128 ))/(-2) }}} 


{{{x = (-4 +- sqrt(144))/(-2) }}} 


{{{x = (-4 +- 12)/(-2) }}} 
x = -16/-2 = 8 
x = 8/-2 = -4