Question 138818
What is the y-intercept of -1/6(y+3)=(1/2)^x-3???? I think the answer is (0,-51) BUT I am not sure :(
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I can't tell whether you mean

{{{(-1/6)(y+3)=(1/2)^(x-3)}}}

or

{{{(-1/6)(y+3)=(1/2)^x-3}}}

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If it was supposed to be this: 

{{{(-1/6)(y+3)=(1/2)^(x-3)}}}

then we substitute 0 for x

{{{(-1/6)(y+3)=(1/2)^(0-3)}}}

{{{(-1/6)(y+3)=(1/2)^(-3)}}}

{{{(-1/6)(y+3)=(2/1)^3}}}

{{{(-1/6)(y+3)=2^3}}}

{{{(-1/6)(y+3)=8}}}

Multiply both sides by {{{-6/1}}}

{{{(-6/1)(-1/6)(y+3)=(-6/1)8}}}

{{{1(y+3)=-48}}}

{{{y+3=-48}}}

{{{y=-48-3}}}

{{{y=-51}}}

So the y-intercept is {{{(matrix(1,3,0,",",-51))}}}
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???? I think the answer is (0,-51) BUT I am not sure :(
<pre><font size = 4 color = "indigo"><b>
It looks as though you are right if it supposed to be

{{{(-1/6)(y+3)=(1/2)^(x-3)}}}

--------------------------------

But if it's supposed to be 

{{{(-1/6)(y+3)=(1/2)^x-3}}}

then we substitute 0 for x

{{{(-1/6)(y+3)=(1/2)^0-3}}}

{{{(-1/6)(y+3)=1-3}}}

{{{(-1/6)(y+3)=-2}}}

Multiply both sides by {{{-6/1}}}

{{{(-6/1)(-1/6)(y+3)=(-6/1)(-2)}}}

{{{1(y+3)=12}}}

{{{y+3=12}}}

{{{y=12-3}}}

{{{y=9}}}

So the y-intercept is {{{(matrix(1,3,0,",",9))}}}

That's what it should be if it supposed 
to be

{{{(-1/6)(y+3)=(1/2)^x-3}}}

Edwin</pre>