Question 138796
Given: {{{(3/2)*ln2x^4-(4/3)*ln2y^6}}}

{{{ln2(x^4)^(3/2)- ln2(y^6)^(4/3)}}}

{{{ln2(x^4)^(3/2) / ln2(y^6)^(4/3)}}}


{{{ln2((x^4)^(3/2) / (y^6)^(4/3))}}}


{{{ln2((x^6) / (y^8))}}}