Question 138801
Graph of {{{y=-(1/2)tan(2x + pi/2)}}} (not the best graph, but it gives you an idea of what it looks like)


{{{ graph( 500, 500, -10, 10, -10, 10,-(1/2)*sin(2x + pi/2)/cos(2x + pi/2)) }}}



Remember the general form is {{{y=a*tan(bx+c)+d}}} where the period is {{{pi/abs(b)}}}, and the phase shift is {{{-c/b}}}




So in this case...


the period is {{{pi/2}}}, the phase shift is {{{-(pi/2)/2=(-pi/2)(1/2)=-pi/4}}}