Question 138686
First graph {{{y=x^2+2x+1}}}


{{{ graph( 500, 500, -10, 10, -10, 10, x^2+2x+1  ) }}} Graph of {{{y=x^2+2x+1}}}




Now graph {{{y=x+3}}}


{{{ graph( 500, 500, -10, 10, -10, 10, x+3  ) }}} Graph of {{{y=x+3}}}



Now graph the two equations together


{{{ graph( 500, 500, -10, 10, -10, 10, x^2+2x+1,x+3  ) }}} Graph of {{{y=x^2+2x+1}}} (red.  Graph of {{{y=x+3}}}(green)



From the graph, we can see that the two equations intersect at the points (-2,1) and (1,4)



So this means that the solutions are 

{{{x=-2}}} and {{{y=1}}}


OR


{{{x=1}}} and {{{y=4}}}