Question 138594
x^2+52=12x
x^2-12x+52=0
using the quadratic equation:{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} we get:
x=(12+-sqrt[-12^2-4*1*52])/2*1
x=(12+-sqrt[144-208])/2
x=(12+-sqrt-64)/2
x=(12+-8i)/2
x=12/2+-8i/2
x=6+-4i answer.