Question 138452
Find the center and radius by completing the square!
x^2+y^2-4ax-6ay+4a=0

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x^2 -4ax + (2a)^2  + y^2 - 6ay + (3a)2 = 4a^2 + 9a^2-4a
(x-2a)^2 + (y-3a)^2 = 13a^2-4a
Center: (2a , 3a) 
Radius: sqrt(13a^2-4a)

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Cheers,
Stan H.