Question 138239
{{{kx^2=2mg(h+x)}}}


{{{kx^2=2mgh+2mgx}}}


{{{kx^2-2mgx-2mgh=0}}}


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}, where {{{a=k}}}, {{{b=2mg}}}, and {{{c=2mgh}}}, so:


{{{x = (-2mg +- sqrt( (2mg)^2-4(k)(2mgh) ))/(2(k)) }}}


{{{x = (-2mg +- sqrt(4m^2g^2-8kmgh))/(2k)}}}


{{{x = (-2mg +- 2sqrt(m^2g^2-2kmgh))/(2k)}}}


{{{x = (-mg +- sqrt(m^2g^2-2kmgh))/k}}}