Question 138245
6x^2-3x=-2
6x^2-3x+2=0
using the quadratic equation we get:{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
x=(3+-sqrt[-3^2-4*6*2])/2*6
x=(3+-sqrt[9-48])/12
x=(3+-sqrt-39)/12
x=(3+-6.245i)/12
x=3/12+-6.245i/12
x=.25+-.52i answers.