Question 138195
If the second number is subtracted from the sum of the first number and 2 times the third number, the result is 1.
a+2c-b = 1
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The third number plus 2 times the first number is 3.
c +2a = 3
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The first number plus 3 times the second number plus the third number is 18.
a+3b+c = 18 
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Find the three numbers. 
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Rearrange the equations:
a  - b  + 2c =  1
2a + 0  +  c =  3
a  + 3b +  c =  18
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Using Matrix methods I get:
a= 0
b= 5
c= 3
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Cheers,
Stan H.