<PRE><B>Question 137992</B>
A researcher collected sample data for 16 women ages 18 to 24. 
The sample had a mean serum cholestrol level of 188.8, with a standard deviation of 8.2.
Assuming that serum cholesterol levels for women ages 18 to 24 are normally distributed find 95% confidence interval for the mean serum cholersrol level of all women in this age group,
x-bar = 188.8
E = 2.132*[8.2/sqrt(16)]= 4.3706
complete the table below
What is the lower limit of the confidence interval? 188.8-4.3706 = 184.4294
what is the upper limit of the confidence interval? 188.8+4.3706 = 192.3706
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Cheers,
Stan H.
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