Question 137998
x^3=27 __ x^3-27=0


factoring difference of cubes __ (x-3)(x^2+3x+9)=0


using quadratic formula __ x=(-3 +- sqrt[(3^2-(4)(1)(9)])/[(2)(1)] __ x=[-3 +- sqrt(-27)]/2
__ x=-3/2 +- [(3/2)sqrt(3)]i


one root is real (3) __ roots are 3+0i, (-3/2)+[(3/2)sqrt(3)]i, (-3/2)-[(3/2)sqrt(3)]i