Question 137991
Not quite.  You have the right idea substituting 0 for x and y, but you are not completely solving the resulting equations:


{{{3(0)=-6x+3}}}
{{{-6x+3=0}}}
{{{-6x=-3}}}
{{{x=(-3)/(-6)=1/2}}}


{{{3y=-6(0)+3}}}
{{{3y=3}}}
{{{y=1}}}


So the x-intercept is ({{{1/2}}},0) and the y-intercept is (0,1)


See graph below for a picture of the situation:


{{{drawing(600,600,-3,3,-3,3,
grid(1),
graph(600,600,-3,3,-3,3,-2x+1),
green(circle(0,1,.05),
locate(.3,1,y-intercept(0,1)),
circle(1/2,0,.05),
locate(.7,-.1,x-intercept(1/2,0)))

)}}}