Question 137954
{{{((4x^2-20x+3)/(2x+1))+((2x^2-25x-27)/(4x+2))}}}
The denominators have a common factor of {{{(2x+1)}}}:
{{{((4x^2-20x+3)/((2x+1)))+((2x^2-25x-27)/2(2x+1))}}} so if you multiply the first fraction by {{{2/2}}} you will then have a common denominatot of {{{(4x+2)}}} and this is the LCD.
{{{(2(4x^2-20x+3)/2(2x+1))+((2x^2-25x-27)/2(2x+1))}}} or...
{{{((8x^2-40x+6)/(4x+2))+((2x^2-25x-27)/(4x+2))}}}
Now you can add the two fractions.
Good luck!