Question 137921
(log base 3 (4)+ log base 2 (9))^2 - (log base 3 (4)- log base 2 (9))^2

Let log3 4 = x and log2 9 = y
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You have:
(x+y)^2 -(x-y)^2

= x^2+2xy+y^2-(x^2-2xy+y^2)

= 4xy
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Substituting bac to logs you get:

= 4(log3 4)(log2 9)

= 4[log4/log3][log9/log2]

= 4[log4/log2][log9/log3]

= 4 [log2 4][log3 9]

= 4 [2][2]

= 16
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Cheers,
Stan H.
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