Question 137893
Call the numbers a, b,  nd c.
{{{a + b + c = 16}}}
{{{a = 2b + 2}}}
{{{a = c - 2}}}
Now solve for b and c in terms of a
{{{2b = a - 2}}}
{{{b = a/2 - 1}}}
and
{{{c = a + 2}}}
{{{a + (a/2 - 1) + (a + 2) = 16}}}
{{{5a/2 + 1 = 16}}}
{{{5a/2 = 15}}}
{{{5a = 30}}}
{{{a = 6}}}
{{{b = a/2 - 1}}}
{{{b = 6/2 - 1}}}
{{{b = 2}}}
{{{c = a + 2}}}
{{{c = 8}}}
The numbers are 6, 2,  and 8