Question 137739
(y-2)^2=5
y^2-4y+4-5=0
y^2+4y-1=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
y=(-4+-sqrt[4^2-4*1-1])/2*1
y=(-4+-sqrt[16+4])/2
y=(-4+-sqrt20)/2
y=(-4+-4.47)/2
y=(-4+4.47)/2
y=-.47/2
y=.235 answer.
y=(-4-4.47)/2
y=-8.47/2
y=-4.235 answer.