<PRE><B>Question 137727</B>
Determine the equation of the line. Put in slope-intercept form, if possible.
Through (2,8), perpendicular to 5x+8y=74
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The given line has slope = -5/8
So the line you want must have slope 8/5 and must pass thru (2,8)
The form of the equation is y = mx + b
You know y=8 when x=2 and you know m=(8/5); solve for &quot;b&quot;:
8 = 2(8/5) + b
b = (40/5)-16/5 = 24/5
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EQUATION:
y = (8/5)x + (24/5)
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{{{graph(400,300,-10,10,-10,10,(8/5)x+(24/5),(-5/8)x+(74/8))}}}
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Cheers,
Stan H.
</PRE>