Question 137676

Distance(d) equals Rate(r) times Time(t) or d=rt;  r=d/t and t=d/r

Let t=time that elapses before they meet
Distance John travels=d
Distance Mike travels=(360-d)
John's time=d/50
Mikes's time=(360-d)/45

Now we know that John's time has to equal Mike's time, so:

d/50=(360-d)/45  multiply each side by 50*45 (or cross multiply)


45d=50(360-d) or
45d=18000-50d  add 50 d to both sides
45d+50d=18000
95d=18000  divide both sides by 95
d=~189.5 mi------------------------------distance John travels (also distance from John's house)
360-d=360-189.5=~170.5 mi---------------------distance Mike travels

John's time: t=d/r=189.5/50=3.79 hr-------------3h 47.4m
Mike's time: t=d/r=170.5/45=3.79 hr--------------3h 47.4m

Time when they meet=10:00AM + 3h 47.4m=1:47.4pm. 

Hope this helps---ptaylor