Question 137534
x^3+4x^2-17x-60 = 0
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I graphed it and found a zero at x=4.
Using synthetic division you get:
4)....1....4....-17....-60
.......1....8.....15...|..0
Remainder: 0
Quotient: (x^2+8x+15)
which factors as (x+5)(x+3)
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Zeroes at x = 4,x=-5,x=-3
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Cheers,
Stan H.