<PRE><B>Question 137362</B>
The 1st question was answered earlier this evening. Can you find it?
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2. An air rescue plane averages 300 miles per hour in still air. It carries fuel for 5 hours of flying time. If, upon takeoff, it encounters a wind of 30 miles per hour, how far can it fly and return safely? (assume that the wind remains constant)
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Original rate: 300 mph ; time = 5 hrs. ; distance = 1500 miles
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With 30 mph wind
rate = 330 mph ; time = x hrs; distance = 330x miles
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against 30 mph wind
rate = 270 mph ; time = 5-x hrs; distance = 270(5-x)= 1350-270x miles
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EQUATION:
distance out = distance back
330x = 1350-270x
600x = 1350
x = 2.25 hrs (time with the wind)
Distance with the wind = 330*2.25 = 742.5
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Round trip distance: 2*742.5 = 1485 miles
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Cheers,
Stan H.

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