Question 137308
Simplify:
{{{((9x^4-72x)/(3x^2-12))*((x^2+x-2)/(4x^3+8x^2+16x))}}} Let's start factoring:
{{{(9x(x^3-8)/3(x^2-4))*((x-1)(x+2)/4x(x^2+2x+4))}}} Cancel 3x in the top with 3x in the bottom.
{{{(3(x^3-8)/(x^2-4))*((x-1)(x+2)/4(x^2+2x+4))}}} Simplify a bit.
{{{3(x^3-8)(x-1)(x+2)/(4(x^2-4)*(x^2+2x+4))}}} Factor the difference of cubes in the top and the difference of squares in the bottom.
{{{(3cross((x-2))cross((x^2+2x+4))(x-1)cross((x+2)))/(4cross((x-2))cross((x+2))cross((x^2+2x+4)))}}} Cancel the like-terms in the top and bottom.
{{{3(x-1)/4}}}