Question 137138
x-4Square root x+3=0
x-4sqrt(x+3) = 0
x^2 = 16(x+3)
x^2-16x-3 = 0
x=[16 +- sqrt(16^2-4*-3)]/2
x=[16 +- 16.3707...]/2
x= 16.1854 or x = -0.18545,,
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Cheers,
Stan H.