Question 137128
if f(x)=ax^2+bx+c
then
 y axis intercept is P=(0,f(0))=(0,c)
x axis intercept are the roots of f(x)
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

f(x)=x^2-5x+6
y axis intercept is P=(0,6)
{{{x = (5 +- sqrt( 25-4*1*6 ))/(2*1) }}} 
x axis intercept are x=2 and x=3
point are (2,0) and (3,0)