Question 137064
ln (x + 6) - ln 10 = ln(x-1) - ln 2 

ln[(x+6)/10] = ln[(x-1)/2]
(x+6)/10 = (x-1)/2
Cross multiply to get:
2x+12 = 10x-10
8x = 22
x = 11/4
------------------

Can you please show me the steps on how to solve this problem along with one like... 
log 3x - 2[logx - log(2+y)]

Comment: You can't solve this one because it is not an equation:

log3x -2logx + 2log(2+y)

= log[(3x*2+y)/x^2]

=========================
Cheers,
Stan H.