Question 136751
Q1. Rearrange x = 1/2 A In (q - 3) + c to obtain q
:
Multiply equation by 2 to get rid of the denominator
2x = A*ln(q-3) + 2c
:
Subtract 2c from both sides:
2x - 2c = A*ln(q-3)
:
Divide both sides by A
{{{((2x-2c))/A}}} = ln(q-3)
:
Use the exponent equivalent of logs
{{{e^(((2x-2c)/A))}}} = q - 3; Note that{{{((2x-2c))/A}}} is the exponent of e
Add 3 to both sides
q = {{{e^(((2x-2c)/A))+3}}}
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Q2. Make y the subject E = P (1 - e^(y - 1))
Divide both sides by P
{{{E/P}}} = {{{1-e^((y-1))}}}
or we can arrange it:
{{{e^((y-1))}}} = 1 - {{{E/P}}}
Find the natural log of both sides(ln of e is 1)
y - 1 = {{{ln(1-(E/P))}}}
Add 1 to both sides:
y = {{{ln(1-(E/P))}}} +1