Question 136911
Hi,

given y = 3^x  and y = 5^x

Here we equate both y
==> 3^x = 5^x

This equation is satisfied only when x = 0 and for no other value will this hold good as the bases are different.

==> 3^0 = 5^0
==> 1 = 1

Thus when x = 0, y = 3^0 = 5^0 = 1

So the only solution is (0, 1)

good luck!!!

dolly