Question 136609
The quadratic formula gives the solutions to any equation of the form {{{ax^2+by+c=0}}}.  Take the coefficient values from your equation and put them into the formula:



{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}


Then do the arithmetic.  Generally, when you are just solving an equation that is not part of a word problem involving measurements, you leave the answer in radical form (unless the radical turns out to be a perfect square).  Just remember to take the square root of any perfect square factors of the number under the radical.  For example, if you had {{{sqrt(50)}}}, that is the same as {{{sqrt(25*2)=sqrt(25)sqrt(2)=5sqrt(2)}}}.