SOLUTION: mary is making a rectangular canvas for her next painting. she wants the length of the canvas to be 4 feet more than twice the width of the canvas. the area of canvas must be 30 sq

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: mary is making a rectangular canvas for her next painting. she wants the length of the canvas to be 4 feet more than twice the width of the canvas. the area of canvas must be 30 sq      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 999866: mary is making a rectangular canvas for her next painting. she wants the length of the canvas to be 4 feet more than twice the width of the canvas. the area of canvas must be 30 square feet. what should be the dimensions of the canvas
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
w and L, width and length;
system%28L=4%2B2w%2CwL=30%29

This will give a quadratic equation allowing to solve first for w.

w%282w%2B4%29=30
2w%5E2%2B4w-30=0
w%5E2%2B2w-15=0
Formula for general solution of a quadratic equation is what could use, but try factoring first.