SOLUTION: Hi! What I am given is- (-2r,r) and (4r+1,5r), and a slope of -3. What the questions are- 1. actual coordinates (solve for r?) 2. point-slope form (for what is given) 3. slope

Algebra ->  Expressions-with-variables -> SOLUTION: Hi! What I am given is- (-2r,r) and (4r+1,5r), and a slope of -3. What the questions are- 1. actual coordinates (solve for r?) 2. point-slope form (for what is given) 3. slope      Log On


   

Question 999794: Hi! What I am given is-
(-2r,r) and (4r+1,5r), and a slope of -3.
What the questions are-
1. actual coordinates (solve for r?)
2. point-slope form (for what is given)
3. slope-intercept form (for what's given)
4. standard form (for what's given)
Thank you!
Found 2 solutions by josgarithmetic, mananth:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
Use formula for slope to solve for r.

%285r-r%29%2F%284r%2B1-%28-2r%29%29=-3
simplify.
4r%2F%286r%2B1%29=-3
4r=-3%286r%2B1%29
4r=-18r-3
22r=-3
highlight%28r=-3%2F22%29


1.
(-2(-3/22),-3/22) and (4(-3/22)+1,5(-3/22))
(3/11,-3/22) and (-6/11+11/11,-15/22)
The points: (3/11,-3/22) and (5/11,-15/22)

Do you still need help with #2, #3, #4 ? You have what you need, which are two points and the slope.

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
slope = %28y1-y2%29%2F%28x1-x2%29
(-2r,r) and (4r+1,5r),

slope = -3
-3=%28r-5r%29%2F%28-2r-%284r%2B1%29%29

-3=%28-4r%29%2F%28-6r-1%29

-3(-6r-1)=-4r
18r+3=-4r
22r=-3
r= -22/3
Plug r to get co ordinates