SOLUTION: Suppose Henry biked from his house to his friend Peter's home at an average rate of 12 miles per hour. When it was time to go home, Henry discovered he had a flat tire, so he walke
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Question 999765: Suppose Henry biked from his house to his friend Peter's home at an average rate of 12 miles per hour. When it was time to go home, Henry discovered he had a flat tire, so he walked home by the same route at an average rate of 4 miles per hour.
a. If the sum of the traveling tu=imes was 1.5 hours, how far is it(exactly) from Henry's house to Peter's house along that route?
b. What was Henry's average speed for the round trip? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Suppose Henry biked from his house to his friend Peter's home at an average rate of 12 miles per hour.
When it was time to go home, Henry discovered he had a flat tire, so he walked home by the same route at an average rate of 4 miles per hour.
:
a. If the sum of the traveling times was 1.5 hours, how far is it(exactly) from Henry's house to Peter's house along that route?
let d = the one-way distance
Write a time equation; time = dist/speed
Bike time + Walk time = 1.5 hrs + = 1.5
Cancel the denominators, multiply equation by 12, you then have
d + 3d = 12(1.5)
4d = 18
d = 18/4
d = 4.5 miles from H's to P's house
:
b. What was Henry's average speed for the round trip?
We know the time and the total distance (2d), average speed (a)
a =
a = 9/1.5
a = 6 mph
