SOLUTION: Find three consecutive odd intergers whose sum is 117.
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Question 99974
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Find three consecutive odd intergers whose sum is 117.
Answer by
checkley71(8403)
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X+X+2+X+4=117
3X=117-6
3X=111
X=111/3
X=37 IS THE FIRST ODD NMBER.
39 & 41 ARE THE OTHER 2 ODD NUMBERS.
PROOF
37+39+41=117
117=117