SOLUTION: ``solve each system of equations by the substitution method 6x+3y=12 5x+10y=16

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Question 999610: ``solve each system of equations by the substitution method
6x+3y=12
5x+10y=16
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
From eq. 1,
3y=-6x%2B12
y=-2x%2B4
Substitute into eq. 2,
5x%2B10%28-2x%2B4%29=16
5x-20x%2B40=16
-15x=-24
x=24%2F15
x=8%2F5
So then,
y=-2%288%2F5%29%2B4
y=-16%2F5%2B20%2F5
y=4%2F5