SOLUTION: write an equation in slope intercept form of the line that passes through the given point and is perpendicular to the given line. Given: (-3,1); y=1/3x+2, (4,-3); 2x-7y=14
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-> SOLUTION: write an equation in slope intercept form of the line that passes through the given point and is perpendicular to the given line. Given: (-3,1); y=1/3x+2, (4,-3); 2x-7y=14
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Question 999556: write an equation in slope intercept form of the line that passes through the given point and is perpendicular to the given line. Given: (-3,1); y=1/3x+2, (4,-3); 2x-7y=14
Solve for y and adjust into slope intercept form.
Slope is .
Determine what is negative reciprocal of .
That would be , and this is the slope of the line PERPENDICULAR to the given .
Line to be found, if in slope-intercept form is and you want to find b.
Use the point which this line must pass through.
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Line sought, in slope-intercept form is . THIS LINE is perpendicular to 2x-7y=14 and passes through the required point (4,-3).
Adjust the line into standard form, IF YOU WANT, since your given line was in standard form.