SOLUTION: What are the zeroes, axis of symmetry, and vertex for the equation (3x^2-x-1=0) Please show steps if you can

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Question 999469: What are the zeroes, axis of symmetry, and vertex for the equation (3x^2-x-1=0) Please show steps if you can
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
Equation or function? As the equation mentioned and shown, it has ZEROS.

(3x --- 1)(x--- 1)=0 seems not factorable.

x=%281%2B-+sqrt%281%5E2-4%2A3%2A%28-1%29%29%29%2F%282%2A3%29

highlight%28x=%281%2B-+sqrt%2813%29%29%2F6%29----------these are the zeros.


The FUNCTION f%28x%29=3x%5E2-x-1, in general form, can be converted into standard form. You can read and study to learn how to do that. Lesson, how to complete the square to solve a quadratic equation; http://www.algebra.com/my/Completing-the-Square-to-Solve-General-Quadratic-Equation.lesson?content_action=show_dev

That will also give information about vertex and axis of symmetry.
Say if you have further trouble with this.


The standard form function through completing the square and arranging is f%28x%29=3%28x-1%2F6%29%5E2-13%2F12; and vertex is ( 1/6, -13/12). Symmetry axis is x=1%2F6.

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Not sure what happened to your posted equation, but it is missing from what you posted. The original equation was 3x%5E2-x-1=0. I am trying to adjust what you posted so the equation shows up there again, at least.