Question 999176:  write an equation in standard form of a line whose x-intercept is an integer and y-intercept is a fraction. Explain how you know that the x-intercept is an integer and y-intercept is a fraction 
 Answer by Theo(13342)      (Show Source): 
You can  put this solution on YOUR website! ax + by = c
 
 
the x-intercept is the value of x when y = 0. 
the y-intercept is the value of y when x = 0.
 
 
when y = 0, ax = c which results in x = c/a
 
 
when x = 0, by = c which results in y = c/b
 
 
in order for c/a to be an integer, c has to be a multiple of a.
 
 
in order for c/b to be a fraction, c must not be a multiple of b.
 
 
if c is a multiple of a, then c can be made equal to a*d, where d is an integer.
 
 
example:
 
 
55 / 5 is an integer because 55 is a multiple of 5. 
55 = 5 * 11, so 55/5 = 11
 
 
56 / 5 is not an integer because 56 is not a multiple of 5.
 
 
-15 / 5 is an integer because 15 is a multiple of 5. 
15 = 5 * 3, so 15/5 = 3
 
 
-16 / 5 is not an integer because 16 is not a multiple of 5.
 
 
so, if you want ax + by = c to have the x-intercept an integer and the y-intercept a fraction, then c must be a multiple of a but not a multiple of b.
 
 
an example would be:
 
 
5x + 6y = 15
 
 
the x intercept is the value of x when y = 0. 
when y = 0, the equation becomes 5x = 15. 
solve for x to get x = 15/5 = 3. 
3 is an integer.
 
 
the y intercept is the value of y when x = 0. 
when x = 0, the equation becomes 6y = 15. 
solve for y to get y = 15/6. 
15/6 is not an integer.
 
 
that's my take.
 
 
an integer can also be described as a fraction where the denominator is equal to 1.
 
 
why is 55/5 an integer?
 
 
multiply numerator and denominator of 55/5 by 1/5 and you get (55*1/3) / (5*1/5) which results in 11/1 which is the same as 11.
 
 
55/5 is therefore an integer because it can be simplified to a ratio where the denominator is equal to 1.
 
 
56/5 cannot be simplified to a ratio where the numerator is an integer and the denominator is equal to 1.
 
 
this is because 56 is not a multiple of 5.
 
 
you can find a number such that the denominator is 1, but the number will not be an integer.
 
 
56/5 = 11.2/1 = 11.2 which is a fraction in decimal form.
 
 
  | 
 
  
 
 |   
 
 |