SOLUTION: Linda was on a long 265 mile road trip. The first part of the trip there was lots of traffic, she only averaged 30 mph. The second part of the trip there was no traffic so she coul

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Linda was on a long 265 mile road trip. The first part of the trip there was lots of traffic, she only averaged 30 mph. The second part of the trip there was no traffic so she coul      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 999160: Linda was on a long 265 mile road trip. The first part of the trip there was lots of traffic, she only averaged 30 mph. The second part of the trip there was no traffic so she could drive 41 mph. If the trip took her 7 hours, how long did she travel at each speed?

Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
Let's call the hours at 30 x and the hours at 41 y:
------------------------
x+y= 7 Subtract x from both sides: y= 7-x Let's use this value for y:
30x+41y = 265
30x+41(7-x)= 265 Multiply on left to get rid of the parenthesis:
30x+287-41x= 265
-11x= -22 Divide both sides by -11
x= -22/-11 And remember that -/- = +
x= 2 She drove at 30mph for 2 hours. And:
7-2= 5 hours at 41mph
-------------------
Proof:
30*2= 60
41*5= 205
_ _ _------
Total: 265 We have the correct answer