Question 999042: A person have some hens and some cows. Number of head is 38 and number of legs 100 then how many cows and hens Found 3 solutions by stanbon, fractalier, ikleyn:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A person have some hens and some cows. Number of head is 38 and number of legs 100 then how many cows and hens.
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Heads Equation:: h + c = 38
Legs Equation:: 2h +4c = 100
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Modify for elimination:
h + c = 38
h + 2c = 50
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Subtract and solve for "c"::
c = 12 (# of cows)
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h = 38-12 = 26 (# of hens)
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cheers,
Stan H.
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You can put this solution on YOUR website! Calls hens and cows, x and y.
Thus x + y = 38
Now when we count legs, we have
2x + 4y = 100
Let's multiply the first equation by two and subtract...
2x + 4y = 100
-(2x + 2y = 76)
which gives
2y = 24
y = 12 cows
x = 26 chickens
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