SOLUTION: x^2+y^2-4y+4=100 how do I solve and get 100 to 0?

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Question 998849: x^2+y^2-4y+4=100
how do I solve and get 100 to 0?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2By%5E2-4y%2B4=100......this is equation of a circle; so, standard formula is %28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2 where h and k are x and y coordinates of the center, and r is a radius
x%5E2%2B%28y%5E2-4y%2B4%29=100...complete square

x%5E2%2B%28y%5E2-4y%2B2%5E2%29=100
x%5E2%2B%28y-2%29%5E2=100 or,
%28x-0%29%5E2%2B%28y-2%29%5E2=100
so, you have h=0,k=2, and r=10
center: at (0,2)