SOLUTION: A car traveling 29 mi/h accelerates uniformly
for 7.5 s, covering 385 ft in this time.
What was its acceleration? Round your
answer to the nearest 100th place.
Answer in units
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-> SOLUTION: A car traveling 29 mi/h accelerates uniformly
for 7.5 s, covering 385 ft in this time.
What was its acceleration? Round your
answer to the nearest 100th place.
Answer in units
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Question 998773: A car traveling 29 mi/h accelerates uniformly
for 7.5 s, covering 385 ft in this time.
What was its acceleration? Round your
answer to the nearest 100th place.
Answer in units of ft/s
What is the final velocity at this time?
Answer in units of ft/s Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! 29 mph = 42.5 f/s
Initial vel u .....42.5
time = 7.5 s.....t
distance = 385 ft ....s
s= ut + 1/2 a t^2
385 = 42.5*7.5+ 1/2 a*7.5^2
385 = 318.75 +1/2 *a *56.25
328.75 = 1/2 *56.25 *a
a= 11.69 ft/s*2
v=u +at
v= 42.5+11.69*7.5
= 130.175 ft/s
